Mental Division Shortcuts Every JNVST Aspirant Should Know
5 September 2026
Division Doesn't Have to Mean Long Division
Long division is reliable but slow — and in a timed exam, slow costs marks. Most division questions that appear in competitive school entrance exams involve "nice" divisors like 5, 25, or 9, and each has a shortcut that skips long division entirely.
Dividing by 5: Double and Shift
Dividing by 5 is the same as multiplying by 2 and then dividing by 10.
84 ÷ 5
- Multiply by 2: 84 × 2 = 168
- Divide by 10: 168 ÷ 10 = 16.8
Dividing by 25: Multiply by 4, Shift Twice
Dividing by 25 is the same as multiplying by 4 and then dividing by 100.
300 ÷ 25
- Multiply by 4: 300 × 4 = 1200
- Divide by 100: 1200 ÷ 100 = 12
Dividing by 9: Use the Digit-Sum Check First
Before dividing by 9, a quick digit-sum check tells you whether the division comes out even: if a number's digits add up to a multiple of 9, the number itself divides evenly by 9.
Quick check: 738 ÷ 9
- Digit sum: 7 + 3 + 8 = 18, and 18 is a multiple of 9 — so this divides evenly
- 738 ÷ 9 = 82
Estimating Before You Divide
For messier divisions, round the divisor and dividend to nearby round numbers first, get a ballpark answer, then adjust.
Estimate 437 ÷ 22
- Round to 440 ÷ 22 = 20
- Since 437 is a little less than 440, the actual answer is a little under 20 — useful for eliminating multiple-choice options fast, even before doing exact division.
Why These Shortcuts Matter
In a timed section, you rarely need the full long-division process — you need a fast, reliable answer or a fast way to eliminate wrong options. Building fluency with "divide by 5," "divide by 25," and digit-sum checks for 9 covers a large share of the division questions that show up in competitive exams.
Practice Tip
Pick ten numbers and divide each by 5 and by 25 using the shortcuts above, checking your work with a calculator afterward. Once these become automatic, use the same combination of exact shortcuts and rough estimation as your default approach whenever a division question appears under time pressure.